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See right interview answers on 30 common job interview questions

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1. Can the sizeof operator be used to tell the size of an array passed to a function?

No. There's no way to tell, at runtime, how many elements are in an array parameter just by looking at the
array parameter itself. Remember, passing an array to a function is exactly the same as passing a pointer to
the first element. This is a Good Thing. It means that passing pointers and arrays to C functions is very

It also means that the programmer must use some mechanism to tell how big such an array is. There are two
common ways to do that. The first method is to pass a count along with the array. This is what memcpy() does, for example:

char    source[ MAX ], dest[ MAX ];
/* ... */
memcpy( dest, source, MAX );

The second method is to have some convention about when the array ends. For example, a C "string" is just
a pointer to the first character; the string is terminated by an ASCII NUL ('\0') character. This is also
commonly done when you have an array of pointers; the last is the null pointer. Consider the following
function, which takes an array of char*s. The last char* in the array is NULL; that's how the function knows
when to stop.

void printMany( char *strings[] )
        int     i;
        i = 0;
        while ( strings[ i ] != NULL )
             puts( strings[ i ] );

Most C programmers would write this code a little more cryptically:

void  printMany( char *strings[] )
        while ( *strings )
                puts( *strings++ );

C programmers often use pointers rather than indices. You can't change the value of an array tag, but because strings is an array parameter, it's really the same as a pointer. That's why you can increment strings. Also,

while ( *strings )

means the same thing as

while ( *strings != NULL )

and the increment can be moved up into the call to puts().

If you document a function (if you write comments at the beginning, or if you write a "manual page" or a
design document), it's important to describe how the function "knows" the size of the arrays passed to it.
This description can be something simple, such as "null terminated," or "elephants has numElephants elements." (Or "arr should have 13 elements," if your code is written that way. Using hard coded numbers
such as 13 or 64 or 1024 is not a great way to write C code, though.)

2. Can you assign a different address to an array tag?

No, although in one common special case, it looks as if you can.
An array tag is not something you can put on the left side of an assignment operator. (It's not an "lvalue,"
let alone a "modifiable lvalue.") An array is an object; the array tag is a pointer to the first element in that

For an external or static array, the array tag is a constant value known at link time. You can no more change
the value of such an array tag than you can change the value of 7.

Assigning to an array tag would be missing the point. An array tag is not a pointer. A pointer says, "Here's
one element; there might be others before or after it." An array tag says, "Here's the first element of an array;
there's nothing before it, and you should use an index to find anything after it." If you want a pointer, use
a pointer.

In one special case, it looks as if you can change an array tag:

void  f( char a[ 12 ] )
        ++a;    /* legal! */

The trick here is that array parameters aren't really arrays. They're really pointers. The preceding example
is equivalent to this:

void  f( char *a )
        ++a;    /* certainly legal */

You can write this function so that the array tag can't be modified. Oddly enough, you need to use pointer

void  f( char * const a )
        ++a;    /* illegal */

Here, the parameter is an lvalue, but the const keyword means it's not modifiable.

3. Do array subscripts always start with zero?

Yes. If you have an array a[MAX] (in which MAX is some value known at compile time), the first element is  a[0], and the last element is a[MAX-1]. This arrangement is different from what you would find in some other languages. In some languages, such as some versions of BASIC, the elements would be a[1] through  a[MAX], and in other languages, such as Pascal, you can have it either way.

This variance can lead to some confusion. The "first element" in non-technical terms is the "zero'th" element according to its array index. If you're using spoken words, use "first" as the opposite of "last." If that's not precise enough, use pseudo-C. You might say, "The elements  a sub one through a sub eight," or, "The second through ninth elements of a."

There's something you can do to try to fake array subscripts that start with one. Don't do it. The technique is described here only so that you'll know why not to use it.

Because pointers and arrays are almost identical, you might consider creating a pointer that would refer to the same elements as an array but would use indices that start with one. For example:

/* don't do this!!! */
int     a0[ MAX ];
int     *a1 = a0 - 1;   /* & a[ -1 ] */

Thus, the first element of a0 (if this worked, which it might not) would be the same as a1[1]. The last element
of a0, a0[MAX-1], would be the same as a1[MAX]. There are two reasons why you shouldn't do this.

The first reason is that it might not work. According to the ANSI/ISO standard, it's undefined (which is a
Bad Thing). The problem is that &a[-1] might not be a valid address; Your program might
work all the time with some compilers, and some of the time with all compilers. Is that good enough?

The second reason not to do this is that it's not C-like. Part of learning C is to learn how array indices work.
Part of reading (and maintaining) someone else's C code is being able to recognize common C idioms. If you
do weird stuff like this, it'll be harder for people to understand your code. (It'll be harder for you to understand
your own code, six months later.)

4. Is it better to use a pointer to navigate an array of values, or is it better to use a subscripted array name?

It's easier for a C compiler to generate good code for pointers than for subscripts.

Say that you have this:

/* X is some type */
X       a[ MAX ];       /* array */
X       *p;     /* pointer */
X       x;      /* element */
int     i;      /* index */

Here's one way to loop through all elements:

/* version (a) */
for ( i = 0; i < MAX; ++i )
        x = a[ i ];
        /* do something with x */

On the other hand, you could write the loop this way:

/* version (b) */
for ( p = a; p < & a[ MAX ]; ++p )
        x = *p;
        /* do something with x */

What's different between these two versions? The initialization and increment in the loop are the same. The
comparison is about the same; more on that in a moment. The difference is between x=a[i] and x=*p. The
first has to find the address of a[i]; to do that, it needs to multiply i by the size of an X and add it to the address of the first element of a. The second just has to go indirect on the p pointer. Indirection is fast; multiplication
is relatively slow.

This is "micro efficiency." It might matter, it might not. If you're adding the elements of an array, or simply
moving information from one place to another, much of the time in the loop will be spent just using the array
index. If you do any I/O, or even call a function, each time through the loop, the relative cost of indexing
will be insignificant.

Some multiplications are less expensive than others. If the size of an  X is 1, the multiplication can be optimized
away (1 times anything is the original anything). If the size of an X is a power of 2 (and it usually is if X is any
of the built-in types), the multiplication can be optimized into a left shift. (It's like multiplying by 10 in
base 10.)

What about computing &a[MAX] every time though the loop? That's part of the comparison in the pointer
version. Isn't it as expensive computing a[i] each time? It's not, because &a[MAX] doesn't change during the
loop. Any decent compiler will compute that, once, at the beginning of the loop, and use the same value each
time. It's as if you had written this:

/* how the compiler implements version (b) */
X       *temp = & a[ MAX ];     /* optimization */
for ( p = a; p < temp; ++p )
        x = *p;
        /* do something with x */

This works only if the compiler can tell that a and MAX can't change in the middle of the loop.
There are two other versions; both count down rather than up. That's no help for a task such as printing the
elements of an array in order. It's fine for adding the values or something similar. The index version presumes
that it's cheaper to compare a value with zero than to compare it with some arbitrary value:

/* version (c) */
for ( i = MAX - 1; i >= 0; --i )
        x = a[ i ];
        /* do something with x */

The pointer version makes the comparison simpler:

/* version (d) */
for ( p = & a[ MAX - 1 ]; p >= a; --p )
        x = *p;
        /* do something with x */

Code similar to that in version (d) is common, but not necessarily right. The loop ends only when p is less
than a. That might not be possible.

The common wisdom would finish by saying, "Any decent optimizing compiler would generate the same
code for all four versions." Unfortunately, there seems to be a lack of decent optimizing compilers in the
world. A test program (in which the size of an X was not a power of 2 and in which the "do something" was
trivial) was built with four very different compilers. Version (b) always ran much faster than version (a),
sometimes twice as fast. Using pointers rather than indices made a big difference. (Clearly, all four compilers
optimize &a[MAX] out of the loop.)

How about counting down rather than counting up? With two compilers, versions (c) and (d) were about
the same as version (a); version (b) was the clear winner. (Maybe the comparison is cheaper, but decrementing
is slower than incrementing?) With the other two compilers, version (c) was about the same as version (a)
(indices are slow), but version (d) was slightly faster than version (b).

So if you want to write portable efficient code to navigate an array of values, using a pointer is faster than
using subscripts. Use version (b); version (d) might not work, and even if it does, it might be compiled into
slower code.

Most of the time, though, this is micro-optimizing. The "do something" in the loop is where most of the
time is spent, usually. Too many C programmers are like half-sloppy carpenters; they sweep up the sawdust
but leave a bunch of two-by-fours lying around.

5. Is it valid to address one element beyond the end of an array?

It's valid to address it, but not to see what's there. (The really short answer is, "Yes, so don't worry about it.")
With most compilers, if you say

int     i, a[MAX], j;

then either i or j is at the part of memory just after the last element of the array. The way to see whether i or j follows the array is to compare their addresses with that of the element following the array. The way to
say this in C is that either

& i == & a[ MAX ]

is true or

& a[ MAX ] == & j

is true. This isn't guaranteed; it's just the way it usually works.
The point is, if you store something in a[MAX], you'll usually clobber something outside the a array. Even
looking at the value of a[MAX] is technically against the rules, although it's not usually a problem.
Why would you ever want to say &a[MAX]? There's a common idiom of going through every member of a
loop using a pointer. Instead of

for ( i = 0; i < MAX; ++i )
        /* do something */;

C programmers often write this:

for ( p = a; p < & a[ MAX ]; ++p )
        /* do something */;

The kind of loop shown here is so common in existing C code that the C standard says it must work.

6. What is the difference between a string and an array?

An array is an array of anything. A string is a specific kind of an array with a well-known convention to
determine its length.

There are two kinds of programming languages: those in which a string is just an array of characters, and those
in which it's a special type. In C, a string is just an array of characters (type char), with one wrinkle: a C string
always ends with a NUL character. The "value" of an array is the same as the address of (or a pointer to) the
first element; so, frequently, a C string and a pointer to char are used to mean the same thing.

An array can be any length. If it's passed to a function, there's no way the function can tell how long the array
is supposed to be, unless some convention is used. The convention for strings is NUL termination; the last
character is an ASCII NUL ('\0') character.

In C, you can have a literal for an integer, such as the value of 42; for a character, such as the value of '*';
or for a floating-point number, such as the value of 4.2e1 for a float or double.

There's no such thing as a literal for an array of integers, or an arbitrary array of characters. It would be very
hard to write a program without string literals, though, so C provides them. Remember, C strings
conventionally end with a NUL character, so C string literals do as well. "six times nine" is 15 characters
long (including the NUL terminator), not just the 14 characters you can see.

There's a little-known, but very useful, rule about string literals. If you have two or more string literals, one
after the other, the compiler treats them as if they were one big string literal. There's only one terminating
NUL character. That means that "Hello, " "world" is the same as "Hello, world", and that

char    message[] =
  "This is an extremely long prompt\n"
  "How long is it?\n"
  "It's so long,\n"
  "It wouldn't fit on one line\n";

When defining a string variable, you need to have either an array that's long enough or a pointer to some
area that's long enough. Make sure that you leave room for the NUL terminator. The following example code
has a problem:

char greeting[ 12 ];
strcpy( greeting, "Hello, world" );    /* trouble */

There's a problem because greeting has room for only 12 characters, and "Hello, world" is 13 characters
long (including the terminating NUL character). The NUL character will be copied to someplace beyond
the greeting array, probably trashing something else nearby in memory. On the other hand,

char   greeting[ 12 ] = "Hello, world";  /* not a string */

is OK if you treat greeting as a char array, not a string. Because there wasn't room for the NUL terminator,
the NUL is not part of greeting. A better way to do this is to write

char    greeting[] = "Hello, world";

to make the compiler figure out how much room is needed for everything, including the terminating NUL character.

String literals are arrays of characters (type char), not arrays of constant characters (type const char). The
ANSI C committee could have redefined them to be arrays of const char, but millions of lines of code would
have screamed in terror and suddenly not compiled. The compiler won't stop you from trying to modify the
contents of a string literal. You shouldn't do it, though. A compiler can choose to put string literals in some
part of memory that can't be modified???in ROM, or somewhere the memory mapping registers will forbid
writes. Even if string literals are someplace where they could be modified, the compiler can make them shared.

For example, if you write

char    *p = "message";
char    *q = "message";
p[ 4 ] = '\0';  /* p now points to "mess" */

(and the literals are modifiable), the compiler can take one of two actions. It can create two separate string
constants, or it can create just one (that both p and q point to). Depending on what the compiler did,  q might
still be a message, or it might just be a mess.

7. What is the difference between array_name and &array_name?

One is a pointer to the first element in the array; the other is a pointer to the array as a whole.

An array is a type. It has a base type (what it's an array of ), a size (unless it's an "incomplete" array), and a
value (the value of the whole array). You can get a pointer to this value:

char a[ MAX ];      /* array of MAX characters */
char *p;            /* pointer to one character */
/* pa is declared below */
pa = & a;
p = a;  /* = & a[ 0 ] */

After running that code fragment, you might find that  p and pa would be printed as the same value; they both
point to the same address. They point to different types of MAX characters.

The wrong answer is

char *( ap[ MAX ] );

which is the same as this:

char *ap[ MAX ];

This code reads, "ap is an array of MAX pointers to characters."

8. Why can't constant values be used to define an array's initial size?

There are times when constant values can be used and there are times when they can't. A C program can use
what C considers to be constant expressions, but not everything C++ would accept.

When defining the size of an array, you need to use a constant expression. A constant expression will always
have the same value, no matter what happens at runtime, and it's easy for the compiler to figure out what
that value is. It might be a simple numeric literal:

char    a[ 512 ];

Or it might be a "manifest constant" defined by the preprocessor:

#define MAX     512
/* ... */
char    a[ MAX ];

Or it might be a sizeof:

char    a[ sizeof( struct cacheObject ) ];

Or it might be an expression built up of constant expressions:

char    buf[ sizeof( struct cacheObject ) * MAX ];

Enumerations are allowed too.

An initialized const int variable is not a constant expression in C:

int     max = 512;      /* not a constant expression in C */

char    buffer[ max ];  /* not valid C */

Using const ints as array sizes is perfectly legal in C++; it's even recommended. That puts a burden on C++
compilers (to keep track of the values of const int variables) that C compilers don't need to worry about.
On the other hand, it frees C++ programs from using the C preprocessor quite so much.